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Re: Stephen's List
Posted By: Howard, on host 205.184.139.118
Date: Wednesday, June 9, 1999, at 13:11:37
In Reply To: Re: Stephen's List posted by enile on Wednesday, June 9, 1999, at 07:14:31:

> > > Also (to the nearest second):
> > > 1: 4.05.27
> > > 2: 4.21.49
> > > 3: 4.38.11
> > > 4: 4.54.33
> > >
> > > enile ;)
> >
> > G*D but you're GUD! How do you do it? I suppose you had use of a PC and a math program. But if you remember I only had use of 'improper fractions' back in 1955 in year 5 of high school (don't ask how old I am), I'd appreciate a few notes on how you approach the problem?
> >
> > Thanks for your time enile ;) you're real sweet!
>
> No PC, no sleight of hand - just good old algebra:
>
> Suppose the time is 4 hours and t minutes
> Each 'hour' on the clock face is 30deg
> Position of hour hand is: (4 x 30deg) + (t/60 x 30deg) = (120 + t/2)deg
> Position of minute hand is: t x 360/60deg = 6t
>
> So, if we want the angle between the hands to be y degrees (where y = -90, 0, 90, 180) we solve the equation:
> 6t - (120 + t/2) = y
> rewritten as t = (120+y)/5.5
> remembering that t returned is in decimal minutes, so to convert to minutes and seconds take the bit after the decimal point (the seconds component) and multiply by 60 (eg 1.5 minutes = 1min + 60x0.5sec).
>
> Always glad to help someone with their homework (can't work out how old you are though;)
>
> en'once was a mathematician'ile

What you talking 'bout, Willis? I mean enile. If you can figure the clock thing, you can figure her age. Just for practice, I graduated from HS in 1953. How old am I? (hint: I spent five years in college, but I got through HS in four.)
How"old codger"ard

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