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Re: Inventory Arrangement Problem
Posted By: gabby, on host 206.64.3.168
Date: Friday, December 22, 2000, at 15:06:43
In Reply To: Re: Inventory Arrangement Problem posted by gabby on Thursday, December 21, 2000, at 20:02:27:

>
> This is what I did.
>
> We want the items in 4 columns, with R per column. N=4R
> We switched rows into columns in creating the problem, and we still want four of them. N=4(4)=16
>
> gab"?"by

...Then I did it a way that actually makes sense, but naturally my connection decided to quit for the day. Maybe this is better.

N-4R=0
N-4[(N+4)/5]=0
N-4N/5-16/5=0
N/5=16/5
N=16

Adding 4 to N in the second step is to make it a multiple of 5. Adding 1, 2, and 3 is also possible, but they produce lower values of N.

gab"Or maybe not."by

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