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 Re: Stephen's List 
 Howard, on host 205.184.139.118
  Wednesday, June 9, 1999, at 13:11:37
  Re: Stephen's List posted by enile on Wednesday, June 9, 1999, at 07:14:31:
> > > Also (to the nearest second):  > > > 1: 4.05.27 > > > 2: 4.21.49 > > > 3: 4.38.11 > > > 4: 4.54.33 > > > > > > enile ;) > > > > G*D but you're GUD! How do you do it? I suppose you had use of a PC and a math program. But if you remember I only had use of 'improper fractions' back in 1955 in year 5 of high school (don't ask how old I am), I'd appreciate a few notes on how you approach the problem?  > > > > Thanks for your time enile ;) you're real sweet! > > No PC, no sleight of hand - just good old algebra: > > Suppose the time is 4 hours and t minutes > Each 'hour' on the clock face is 30deg > Position of hour hand is: (4 x 30deg) + (t/60 x 30deg) = (120 + t/2)deg > Position of minute hand is: t x 360/60deg = 6t > > So, if we want the angle between the hands to be y degrees (where y = -90, 0, 90, 180) we solve the equation: > 6t - (120 + t/2) = y > rewritten as t = (120+y)/5.5 > remembering that t returned is in decimal minutes, so to convert to minutes and seconds take the bit after the decimal point (the seconds component) and multiply by 60 (eg 1.5 minutes = 1min + 60x0.5sec).  > > Always glad to help someone with their homework (can't work out how old you are though;) > > en'once was a mathematician'ile
  What you talking 'bout, Willis?  I mean enile.  If you can figure the clock thing, you can figure her age.  Just for practice, I graduated from HS in 1953.  How old am I? (hint: I spent five years in college, but I got through HS in four.) How"old codger"ard 
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